129.
ա) (x-4)2 > 0
(x-4)2 = 0
x — 4 = 0
x = 4
x∈(-∞; 4) U (4; +∞)
գ) (2x — 3)2 > 0
(2x — 3)2 = 0
2x — 3 = 0
2x = 3
x = 3/2
x∈(-∞; 3/2) U (3/2; +∞)
130.
ա) x2 — 4x + 4 > 0
x2 — 4x + 4 = 0
D = b2 — 4ac = 16 — 16 = 0
x = b/2a = 4/2 = 2
x∈(-∞; 2) U (2; +∞)
բ) x2 — 2x + 1 > 0
x2 — 2x + 1 = 0
D = b2 — 4ac = 4 — 4 = 0
x = -b/2a = 2/2 = 1
x∈(-∞; 1) U (1; +∞)
գ) x2 + 10x + 25 < 0
x2 + 10x + 25 = 0
D = b2 — 4ac = 100 — 4 * 25 = 0
x = -b/2a = -10/2 = -5
Պատ.՝ O
դ) x2 — 8x + 16 < 0
x2 — 8x + 16 = 0
D = b2 — 4ac = 64 — 64 = 0
x = -b/2a = 8/2 = 4
Պատ.՝ O
131.
ա) x2 — 2x + 1 > 0
x2 — 2x + 1 = 0
D = b2 — 4ac = 4 — 4 = 0
x = -b/2a = 2/2 = 1
x∈(-∞; 1) U (1; +∞)
բ) x2 + 6x + 9 < 0
x2 + 6x + 9 = 0
D = b2 — 4ac = 36 — 36 = 0
x = -b/2a = -6/2 = -3
Պատ.՝ O
գ) x2 + 4x + 4 < 0
x2 + 4x + 4 = 0
D = b2 — 4ac = 16 — 16 = 0
x = -b/2a = -4/2 = -2
Պատ.՝ O
դ) 4x2 — 4x + 1 > 0
4x2 — 4x + 1 = 0
D = b2 — 4ac = 16 — 16 = 0
x = -b/2a = 4/8 = 1/2
x∈(-∞; 1/2) U (1/2; +∞)
Նանե Խաչատրյան 